Election in Pennsylvania
1840 United States presidential election in Pennsylvania
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← 1836 | October 30 – December 2, 1840 | 1844 → |
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| | | Nominee | William Henry Harrison | Martin Van Buren | | Party | Whig | Democratic | Home state | Ohio | New York | Running mate | John Tyler | none | Electoral vote | 30 | 0 | Popular vote | 144,010 | 143,676 | Percentage | 50.00% | 49.88% | |
County Results Harrison 50-60% 60-70% 70–80% | Van Buren 50-60% 60-70% 70-80% 80-90% | |
President before election Martin Van Buren Democratic | Elected President William Henry Harrison Whig | |
Elections in Pennsylvania |
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The 1840 United States presidential election in Pennsylvania took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.
Pennsylvania voted for Whig challenger William Henry Harrison over Democratic incumbent Martin Van Buren by just 334 votes, a margin of 0.12%. It is the narrowest margin of victory in a presidential election in Pennsylvania history, with Donald Trump's 2016 win following close behind at 0.72%.
Results
See also
References
- ^ "1840 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 4, 2012.